Probably because when something is popular, they will produce many of it. Nowadays, ICs are very cheap compared to transistors. Our transformer is 0.25A, thus we should use 500uF. But if fewer capacitances, there will be a higher level of ripple voltage. If using more capacitances, the effect is lesser until wasted in vain. If the current of the transformer is 1A, we should use a 2,000uF capacitor. Therefore, a 0.25A transformer is more than enough.Īccording to my own experience the rough estimate of C1 that’s easy and works well is: The proper voltage level is 12V for this circuit, it is also easy to find too.Īnd this circuit requires very little amount of current. Normally, the secondary coil of a transformer will be 9V, 12V, 15V, 24V, etc. ![]() The important thing is choosing a transformer. It receives the DC voltage from the unregulated power supply in the same way as the first circuit. The output current can be set with R1, we set it to about 50mA. The Zener Diode will keep the 9V constant voltage to load. The output voltage is fixed at 9V according to the 9V Zener diode voltage. Because we just want to use it for real hobby-level only. I tend to avoid complicated calculations. It can deriver output current of about 30mA to 50mA. In this case, using the Zerner regulator is a better choice. If your load requires a little current but a steady voltage such as a transistor pre-amplifier circuit, battery indicator circuit, etc. How to choose components, Learn HERE: Unregulated Power Supply Simplest 9V DC regulator circuit using Zener diode We have to use a 1A transformer, 1N4007 Diode made for 1A current and a 2,200uF C1 capacitor. As well as the diode current has to be changed to that of the transformer’s current, you also have to increase the capacitance of the capacitor.įor example, if we need 1A output current. But if you want more output current, you need to change your transformer to the higher current one to match your desired current. This circuit can output a current of 0.5A limited by a 0.5A transformer we currently using. Now the output voltage is DC and the voltage rise up to 8.9V.įrom this simple formula of DCV = ACV × 1.414 To get a smoother DC voltage and low ripple voltage. The transformer-Converts a high voltage AC-main to low ACV at about 6.3V.īridge rectifier-It will rectify the voltage from AC (Alternating Current) to DC (Direct Current).įilter capacitor-Smooth up the pulsating voltage from a rectifier to a steady direct current (DC).Īdding more capacitors in parallel with C1 for more capacitance. The principle of this circuit is very simple by only having 3 main components. It has quite a weight because of the transformer inside. Which is used extensively in an AC adapter in the old days. ![]() This circuit is an unregulated power supply circuit. We can use common power supplies, so there is no point in using a larger circuit. Sometimes our load only required a low current or an uncomplicate load such as light bulbs, a small DC motor, etc. Comparable to “do not use a sledgehammer to crack a nut”. When choosing the circuit, I always use the concept of economical and suitable first. Most straightforward 9V power supply circuit Since there are many circuits in this list, we will be listing these circuits from simple to hard in terms of complexity. For normal usage, it is easier and more efficient to use one IC instead of transistors. Because the IC consists of many transistors. Noted that if we compare complexity between IC and transistors, surely IC will be more complex. It has been working well during our testing session. There are both transistor circuits and an IC version, so my daughter to learn about this IC circuit. We will bring up these 6 example circuits, by focusing on inexpensiveness, few components used, and high effectiveness.
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